Question

derive an expression for rate constant of first order reaction ​

Answer 1

Explanation:

For a 1st order reaction: A→Products; the rate of reaction at [A]=0. 2M is 1×10−3 mol L−1s−1 reaction will be 75% completed in.

Answer 2

Answer:

First-Order Reactions

A first-order reaction depends on the concentration of one reactant, and the rate law is: r=−dAdt=k[A] r = − dA dt = k [ A ] .

r=−d[A]dt=k[A]

2N2O5(g)→4NO2(g)+O2(g)

Rate=k[N2O5]m.

rate=k[N2O5]1=k[N2O5]

1.4×10−3=k(0.020)

k=0.070s−1.