Question

find three rational numbers between bracket a minus b power minus 1 and bracket a minus 1 and b minus one given that a equal to 1 upon 6 and b equal to 1 upon 8​

Answer 1

Answer:

{(a-b)^{-1} + (a-1)} / 2

{ (a-1) + (b-1) } /2

{ (a-b)^{-1} + (b-1) } / 2

Step-by-step explanation:

Rational Number: If m and n be two rational numbers such that m < n then 1/2 (m + n) is a rational number between m and n.

Given,

(a-b)^{-1}

(a-1)

(b-1)

Where,

a = 1/6

b = 1/8

Now,

Find rational number between (a-b)^{-1} and (a-1)

we have,

=1/2 (m+n)

= 1/2 ((a-b)^{-1} + (a-1) )

= 1/2 (( (1/6) - (1/8)^{-1} ) + (1/6) -1 ) ) ....put values of a and b

likewise, we can find for

(a-1) and (b-1)

i.e. {(a-1) + (b-1) } / 2