Derive an expression for the current in a circuit with external resistance r (a) n identical cells of emf e and internal resistance r are connected in series (b) m identical cells are connected in parallel
Answers
Answered by
24
I = E/(R+r)
where I = current
E = emf
R = external resistance
r = total internal resistance
For resistors in series;
Total r = r1+r2+rn
For resistors in parallel
Total r.= 1/r1 + 1/r2 + 1/rn
where I = current
E = emf
R = external resistance
r = total internal resistance
For resistors in series;
Total r = r1+r2+rn
For resistors in parallel
Total r.= 1/r1 + 1/r2 + 1/rn
Answered by
0
HOPE IT HELPS YOU
Attachments:
Similar questions