Derive an expression for the excess pressure inside a soap bubble ?
Answers
Answered by
9
Heya,Im a new user (teacher of physics just came to know about this site and decided to help you!)
Good question!
____________________
Now time to unlock its answer!!
let atmospheric pressure=Po
pressure due to charge on bubbles(P)=¥^2/2€
where ¥ is surface charge density and € is permetivity of medium.
now
Pnet=Pi+P-Po
where Pi is initial pressure of bubble
__________________________
Pnet=Pi+P-Po
4T/r=(Pi-Po)+¥^2/2€
here T is surface tension in bubble and r is the radius of bubble .
(Pi-Po)=4T/r- ¥^2/2€
so,
excees pressure =4T/r- ¥^2/2€
because difference of initial pressure and atmospheric is known as excess pressure in bubble.
___________________
Good question!
____________________
Now time to unlock its answer!!
let atmospheric pressure=Po
pressure due to charge on bubbles(P)=¥^2/2€
where ¥ is surface charge density and € is permetivity of medium.
now
Pnet=Pi+P-Po
where Pi is initial pressure of bubble
__________________________
Pnet=Pi+P-Po
4T/r=(Pi-Po)+¥^2/2€
here T is surface tension in bubble and r is the radius of bubble .
(Pi-Po)=4T/r- ¥^2/2€
so,
excees pressure =4T/r- ¥^2/2€
because difference of initial pressure and atmospheric is known as excess pressure in bubble.
___________________
KunalTheGreat:
hello sir!
Similar questions