Derive an expression for the heat produced in time 't' in a wire or resistance 'R',which carrying a conductor 'I'?
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Answered by
296
Here is your answer-
Consider a resistor of Resistance R. Let the current flowing through the resistor be I and potential difference across its ends be V.
In time t, let Q amount of charge flows through the resistor.
Work done on Moving charge will be,
W =V x Q ---------(1).
According to the definition of electric current,
Q = I x t -----------(2).
Putting equation (2) in (1),
W = V x I x t.
And the work done is dissipated as heat.
Therefore,
Heat produced, H=W=V x I x t => VIt.
H= VIt.
According to Ohm's law V= IR.
Putting this in equation(2), we get,
H= IR x It.
Therefore, Heat= I2(square)Rt.
I square x R x t.
Consider a resistor of Resistance R. Let the current flowing through the resistor be I and potential difference across its ends be V.
In time t, let Q amount of charge flows through the resistor.
Work done on Moving charge will be,
W =V x Q ---------(1).
According to the definition of electric current,
Q = I x t -----------(2).
Putting equation (2) in (1),
W = V x I x t.
And the work done is dissipated as heat.
Therefore,
Heat produced, H=W=V x I x t => VIt.
H= VIt.
According to Ohm's law V= IR.
Putting this in equation(2), we get,
H= IR x It.
Therefore, Heat= I2(square)Rt.
I square x R x t.
Answered by
79
Hui friends
Let's take the values in variables
Let current be I
Potential difference be V
Amount ofWork done be W
Charge be Q
And time be t
We know that work done is equal to the product of potential difference and charge
i.e. W = VQ---------------1
Also Q = It---------------2
Therefore from 1 & 2
We can say that
W= VIt
Also we know that
Work done = Energy = Heat
Thus, we can write that
Heat(H)= VIt
Hence proved
Hope it might help you.
If it has helped then just say a thanks
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