Derive an expression for the kinetic energy of an object of mass 'm' moving horizontally with a uniform velocity 'v'
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3
Consider a body of mass "m" moving with an initial velocity "u".
A constant force "F" acts on it and the velocity changes to "v".
Let "s" be the distance covered and "a" be the constant acceleration
We know that
v² - u² = 2as
s =
We know that ,
Work done = Force(F) × displacement (s)
F = ma
W = ma ×
["a" gets cancelled ]
W = m ×
= m[v² - u² ]
When , initial velocity , u = 0
W = mv²
K.E = Work done
= mv²
A constant force "F" acts on it and the velocity changes to "v".
Let "s" be the distance covered and "a" be the constant acceleration
We know that
v² - u² = 2as
s =
We know that ,
Work done = Force(F) × displacement (s)
F = ma
W = ma ×
["a" gets cancelled ]
W = m ×
= m[v² - u² ]
When , initial velocity , u = 0
W = mv²
K.E = Work done
= mv²
Answered by
2
Answer:
KE = work done = mv²
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