derive an expression for the Newton's second law of motion
Answers
Answered by
12
Hey mate !!! here is the ans
Attachments:
Answered by
3
✴✴ Hey friends!!✴✴
------------------------------------------------------------
✴✴ Here is your answer↓⬇⏬⤵
⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇
⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵
=> According to Newton's second law of motion:-)
↪➡ Acceleration produce in a body is directly proportional to the applied force and inversely proportional to the mass of the body.
▶⏩ Derivation:-)
↪➡ Suppose body having mass ‘m’ and force ‘f’ acts on a body, if acceleration produced in a body be ‘a’ then,,
=> According to Newton's second law of motion:-)
↪➡ a œ f. ...................(1) m is constant.
[ œ = proportionality sign]
↪➡ a œ 1/f ..................(2) f is constant.
:-! Combining equation (1) and (2) .
↪➡ a œ f/m.
↪➡ a = kf/m. [ k is constant].
→ If taking m= 1kg, f= 1N, a= 1m/sec².
→ then, k= 1.
↪➡ a= 1×f/m.
↪➡ f= ma.✔✔.
✴✴ hence, it is derived ✴✴.
✴✴ Thanks!!✴✴.
☺☺☺ hope it is helpful for you ✌✌✌.
------------------------------------------------------------
✴✴ Here is your answer↓⬇⏬⤵
⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇⬇
⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵⤵
=> According to Newton's second law of motion:-)
↪➡ Acceleration produce in a body is directly proportional to the applied force and inversely proportional to the mass of the body.
▶⏩ Derivation:-)
↪➡ Suppose body having mass ‘m’ and force ‘f’ acts on a body, if acceleration produced in a body be ‘a’ then,,
=> According to Newton's second law of motion:-)
↪➡ a œ f. ...................(1) m is constant.
[ œ = proportionality sign]
↪➡ a œ 1/f ..................(2) f is constant.
:-! Combining equation (1) and (2) .
↪➡ a œ f/m.
↪➡ a = kf/m. [ k is constant].
→ If taking m= 1kg, f= 1N, a= 1m/sec².
→ then, k= 1.
↪➡ a= 1×f/m.
↪➡ f= ma.✔✔.
✴✴ hence, it is derived ✴✴.
✴✴ Thanks!!✴✴.
☺☺☺ hope it is helpful for you ✌✌✌.
Similar questions
English,
7 months ago
Social Sciences,
7 months ago
Hindi,
7 months ago
English,
1 year ago
Math,
1 year ago
Environmental Sciences,
1 year ago
Science,
1 year ago