Physics, asked by AMHURDLESTAR, 4 months ago

Derive an expression for the resistance of the galvanometer by using meter bridge.​

Answers

Answered by omsairammk
0

Answer:

500bridge meter OK man bye

Answered by rigveenkaur2008
2
Kelvins method to determine the resistance of the galvanometer by using a meter bridge:
A galvanometer whose resistance 'G is to be determined is connected in one gap (left gap) of a Wheatstones meter bridge and a resistance box is connected in the other gap (right gap).
G : Galvanometer
R : Resistance from the resistance box
AC : Metal wire one meter long
Rh : Rheostat
E : Cell.
K :Plug key
K : Jockey
A cell of emf 'E', key K and rheostat Rh are connected in series with the bridge wire AC. The junction B of the galvanometer and the resistance box is connected to the jockey which can slide along wire AC.
A suitable resistance K is taken in the resistance box and a current J is sent round the circuit. Without touching the jockey to any point of AC, note the deflection in the galvanometer.
A rheostat is adjusted to get a suitable deflection (e.g. 0.15, 20 divisions) in the galvanometer.
Place the jockey at points A and C, and see the deflection on the galvanometer. It should be on opposite sides. Kelvins method is a deflection method. The point D is called the balanced point.





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