Question

Derive an expression for velocity constant of a second order reaction

Answer 1

Answer:

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Explanation:

for a second order reaction

rate= k[conc.]^2

[ mol.L^(-1) ]/s = [ mol.L^(-1) ]^2

(mol L^-1)/s × 1/ (mol L^-1)^2

k= rate constant =  mol^(-1) Ls^(-1)

so answer is −d[R]/dt=k[R]^2