Question

Derive an expression for vertical path of a projectile thrown at an angle theta with velocity u

Answer 1

$\huge\mathfrak\pink{anSwEr}$

y = y

y° = 0

Uy ( velocity along y axis) = usin theta

t = t

Ay = acceleration along y axis

y = y° + Uyt + 1/2Ayt²

y = 0 + usin thata ×t + 1/2 Ayt²

but we know that t = x/ u cos theta

y = u sin thata (x/ucos theta) + 1/2 ay (x/ ucos theta)²

y = tan theta ×x + Ayx² /2u²cos²theta

$\huge{\bf{\blue{\fbox{\underline{\color{orange}</p><p>{hoPe\:iT\:heLpS\:!! }}}}}}$

Answer 2

$\huge\red{hElLo}$

refer to attachment !!!

hope it helps u ❤