derive an expression of kinetic energy of a body of mass M rotating uniformely about a given axis.Show that the rotational kinetic energy is equal to= 1/2M *(L/M)².
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Answer:
KE_rot=1/2 Iω² , I=moment of inertia, L=angular momentum
but ω=L/I
KE_rot=1/2 I*(L/I)²
Explanation:
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