derive an expression when number of resistors are connected in series
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hope you are helpfull
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boss009:
cut I
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after this
I×R=I×R1+I×R2+I×R3
I×R=I(R1+R2+R3)[IWILL BE CANCEL]
R=R1+R2+R3.….
I hope you get it
I×R=I×R1+I×R2+I×R3
I×R=I(R1+R2+R3)[IWILL BE CANCEL]
R=R1+R2+R3.….
I hope you get it
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