determine k so that 4k+8,2k 2 +3k+6,3k 2 +4k+4 are three consecutive terms of an A.P.
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4k+8 ,2k+2+3k+6, 3k+2+4k+4 are in AP.
We know that 2*2nd term = Sum of 1st and 3rd term
i.e. 2*(2k+2+3k+6) = 4k +8 +3k+2+4k+4.
thus, k= 2.
4k+8 ,2k+2+3k+6, 3k+2+4k+4 are in AP.
We know that 2*2nd term = Sum of 1st and 3rd term
i.e. 2*(2k+2+3k+6) = 4k +8 +3k+2+4k+4.
thus, k= 2.
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