Physics, asked by GothaalaSheoran5372, 1 year ago

Derive de broglie equation for microscopic particles

Answers

Answered by terminator1857
25

De Broglie first used Einstein's famous equation relating matter and energy:

E=mc^{2}            (1.1)

with

E  = energy,

m  = mass,

c  = speed of light

Using Planck's theory which states every quantum of a wave has a discrete amount of energy given by Planck's equation:

E=hν                 (1.2)

with

E  = energy,

h  = Plank's constant (6.62607 x 10-34 J s),

ν = frequency

Since de Broglie believed particles and wave have the same traits, he hypothesized that the two energies would be equal:

mc2=hν                (1.3)

Because real particles do not travel at the speed of light, De Broglie submitted velocity ( v ) for the speed of light ( c ).

mv2=hν                 (1.4)

Through the equation  λ , de Broglie substituted  v/λ  for  ν  and arrived at the final expression that relates wavelength and particle with speed.

mv2=hvλ                 (1.5)

Hence

λ=hvmv2=hmv           (1.6)

A majority of Wave-Particle Duality problems are simple plug and chug via Equation  1.6  with some variation of canceling out units

Answered by sahooabhi135
5

De Broglie first used Einstein's famous equation relating matter and energy:



E=            (1.1)


with



E  = energy,


m  = mass,


c  = speed of light


Using Planck's theory which states every quantum of a wave has a discrete amount of energy given by Planck's equation:


E=hν                 (1.2)


with


E  = energy,


h  = Plank's constant (6.62607 x 10-34 J s),


ν = frequency


Since de Broglie believed particles and wave have the same traits, he hypothesized that the two energies would be equal:


mc2=hν                (1.3)


Because real particles do not travel at the speed of light, De Broglie submitted velocity ( v ) for the speed of light ( c ).


mv2=hν                 (1.4)


Through the equation  λ , de Broglie substituted  v/λ  for  ν  and arrived at the final expression that relates wavelength and particle with speed.


mv2=hvλ                 (1.5)


Hence


λ=hvmv2=hmv           (1.6)


A majority of Wave-Particle Duality problems are simple plug and chug via Equation  1.6  with some variation of canceling out units


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