Derive de broglie equation for microscopic particles
Answers
De Broglie first used Einstein's famous equation relating matter and energy:
E= (1.1)
with
E = energy,
m = mass,
c = speed of light
Using Planck's theory which states every quantum of a wave has a discrete amount of energy given by Planck's equation:
E=hν (1.2)
with
E = energy,
h = Plank's constant (6.62607 x 10-34 J s),
ν = frequency
Since de Broglie believed particles and wave have the same traits, he hypothesized that the two energies would be equal:
mc2=hν (1.3)
Because real particles do not travel at the speed of light, De Broglie submitted velocity ( v ) for the speed of light ( c ).
mv2=hν (1.4)
Through the equation λ , de Broglie substituted v/λ for ν and arrived at the final expression that relates wavelength and particle with speed.
mv2=hvλ (1.5)
Hence
λ=hvmv2=hmv (1.6)
A majority of Wave-Particle Duality problems are simple plug and chug via Equation 1.6 with some variation of canceling out units
De Broglie first used Einstein's famous equation relating matter and energy:
E= (1.1)
with
E = energy,
m = mass,
c = speed of light
Using Planck's theory which states every quantum of a wave has a discrete amount of energy given by Planck's equation:
E=hν (1.2)
with
E = energy,
h = Plank's constant (6.62607 x 10-34 J s),
ν = frequency
Since de Broglie believed particles and wave have the same traits, he hypothesized that the two energies would be equal:
mc2=hν (1.3)
Because real particles do not travel at the speed of light, De Broglie submitted velocity ( v ) for the speed of light ( c ).
mv2=hν (1.4)
Through the equation λ , de Broglie substituted v/λ for ν and arrived at the final expression that relates wavelength and particle with speed.
mv2=hvλ (1.5)
Hence
λ=hvmv2=hmv (1.6)
A majority of Wave-Particle Duality problems are simple plug and chug via Equation 1.6 with some variation of canceling out units
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