derive de-broglie wavelength of electron
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the case of electrons that is λde Broglie=hpe=hme⋅ve The acceleration of electrons in an electron beam gun with the acceleration voltage Va results in the corresponding de Broglie wavelength λde Broglie=hme⋅√2⋅eme⋅Va=h√2⋅me⋅e⋅Va Proof of the de Broglie hypothesis will be experimentally demonstrated with the help of ...
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