Question

Derive equation for Time of flight of angular projectile

Answer 1

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Answer 2

Answer:

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To find the time of flight, determine the time the projectile takes to reach maximum height. The time of flight is just double the maximum-height time.

Start with the equation:

vy = voy + ay t

At maximum height, vy = 0.

The time to reach maximum height is t1/2 = - voy / ay

Time of flight is t = 2t1/2 = - 2voy / ay

Plugging in voy = vo sin(q) and ay = -g, gives:

Time of flight is t = 2 vo sin(q) / g

where g = 9.8 m/s2

The time of flight is also determined solely by the initial velocity in the y direction and the acceleration due to gravity.

Explanation:

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