Question

Derive expression for electric field intensity due to infinitely long
Straight charged wire.​

Answer 1

Answer:

Explanation:

the electric field of an infinite line charge with a uniform linear charge density can be obtained by a using Gauss' law. Considering a Gaussian surface in the form of a cylinder at radius r, the electric field has the same magnitude at every point of the cylinder and is directed outward.  HOPE IT HELPS U BUDDY...

Answer 2

Explanation:

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Using Gauss�s law, derive expression for intensity of electric field at any point near the infinitely long straight uniformly charged wire. The electric field components in the following figure are `E_(x) = alphax, E_(y) = 0, E_(z) = 0, \" in which \" alpha = 400 N//C` m.

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