Physics, asked by Anonymous, 1 year ago

Derive expression for Escape velocity'----gravitation chapter i need it very urgent plzzźzzzz.....

Answers

Answered by sindureddy

when a object is thrown vertically upwards, it reaches a certain height and comes back to earth . but when it is given greater initial velocity , it reaches greater height before coming back .an object can thrown up with a certain minimum initial velocity,so that the object goes beyond the earth's gravitational feild and escape from earth ,this velocitiy is known as escape velocity of earth

Anonymous: but i need its derivation

sindureddy: but the derivation is too long

Anonymous: Plz give it

Anonymous: i need it

Anonymous: tomorrow is my exam

Answered by adhnanceeyem

Escape velocity is the min speed required for a satellite to completely escape from the earths orbit.

adhnanceeyem: i ill try to do it

adhnanceeyem: can you wait a lil bit

adhnanceeyem: if you dont mind

Anonymous: okkk

Anonymous: i willl

Anonymous: plz fast

adhnanceeyem: ok

Anonymous: plz fast

adhnanceeyem: Suppose that the planet be a perfect sphere of radius R having mass M. Let a body of mass m is to be projected from point A on the earth's surface as shown in the figure. Join OA and produce it further. Let us take two points P and Q which are at distances x and (x + dx) from the center of the earth.
let the minimum velocity to escape from the earth's surface be ve.
Hence, total work done is W=GMm/R

adhnanceeyem: bye

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