Physics, asked by Anonymous, 1 year ago

Derive expression for velocity of a ring, solid cylinder and solid sphere having same radii rolling down the smooth inclined plane without slipping.

Answers

Answered by Omnamhashivay
19

v =  \sqrt{2gh \div (1 + ( {k}^{2}  \div  {r}^{2} ))}

 {k}^{2}  \div  {r}^{2} for \: ring = 1 \\ for \: solid \: cylinder =  \frac{1}{2}  \\ for \: solid \: sphere =  \frac{2}{5}

derivation-

applying come

k1+u1=k2+u2

0+mgh=1/2mv^2(1+ksq/r sq)

on rearranging u get it

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