Physics, asked by samiksha449, 7 months ago

derive expression of the electric field just outside a charged conductor​

Answers

Answered by Anonymous
3

Explanation:

If the charge on conductor A is positive, →E is directed along the outward drawn normal. since E is the same at all points on the curved surface. Now, ∫dS= area of the curved surface =2πrl, where l is the length of the cylinder as shown in the figure.

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Answered by dhareaveer
0

Answer:

the charge on conductor A is positive, →E is directed along the outward drawn normal. since E is the same at all points on the curved surface. Now, ∫dS= area of the curved surface =2πrl, where l is the length of the cylinder as shown in the figure.

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