Question

Derive graphically the equation of motion for position-velocity relation of a body moving with uniform acceleration
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Answer 1

Answer:

okay.  ...

Explanation:

Answer 2

Answer:

Imagine an item it is transferring alongside a immediately line. If we realize that its function at any time t is s of t, this is it is function s of t, it is speed v of t is the spinoff of s of t and its acceleration is the spinoff of speed.

Final speed (v) squared equals preliminary speed (u) squared plus  instances acceleration (a) instances displacement (s). v²=u²+2 a s. Solving for v, very last speed (v) equals the rectangular root of preliminary speed (u) squared plus  instances acceleration (a) instances displacement (s).

Velocity is the velocity and course of movement of an item. In different words, speed is the price of extrade of function of an item (in which function consists of course via way of means of specifying whether or not the item is transferring backwards or forwards on a line, or transferring sideways or up and down in  or 3 dimensions).

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