derive kinetic energy formula
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From equations of motion, the relation connecting the initial velocity (u) and final velocity (v) of an object moving with a uniform acceleration a, and the displacement, s is
But from Newton’s second law of motion F = m a.
work done by the force, F is written as the following:
w = ma(v^2 - u^2/2a) = 1/2m(v^2 - u^2)
If the object is starting from its stationary position, that is, u = 0, then
w = 1/2mv^2
From work and energy theorem, work done is equal to the change in the kinetic energy of the object.
w = (1/2) mv ^2
If u = 0, the work done will be,
Thus the kinetic energy possessed by an object of mass, m and moving with a uniform velocity, v is
K.E = (1/2) mv^ 2
I hope this helped you
Please mark my answer as the brainliest.
But from Newton’s second law of motion F = m a.
work done by the force, F is written as the following:
w = ma(v^2 - u^2/2a) = 1/2m(v^2 - u^2)
If the object is starting from its stationary position, that is, u = 0, then
w = 1/2mv^2
From work and energy theorem, work done is equal to the change in the kinetic energy of the object.
w = (1/2) mv ^2
If u = 0, the work done will be,
Thus the kinetic energy possessed by an object of mass, m and moving with a uniform velocity, v is
K.E = (1/2) mv^ 2
I hope this helped you
Please mark my answer as the brainliest.
Answered by
2
v ^ 2 - u ^ 2 = 2as… This statement states that a work W is done by a body to move from one position to another by a distance s when the force F is applied to a body at rest. This work done on the body is because of Kinetic energy (K.E) of the body.
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