Question

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Answer 1

$\boxed{Solution \Rightarrow}$



Given,



For the hollow cylindrical pipe ,



Inner circumference = 44 dm = 4.4 m



Outer circumference = 45 dm = 4.5 m



Height of the cylindrical pipe = 3.5 m



$\therefore Inner\: curved \:surface\: area\: \\ = \:Inner\: circumference × Height$



= 4.5 m × 3.5 m



= 15.4 sq.m



And,



Outer curved surface area = Outer circumference × Height



= 4.5 m × 3.5 m



= 15.75 sq.m



$\therefore Total\: surface \:area \:of\: the \:pipe\: that\: is\: \\ to\: be\: painted\: \\ =\: Inner\: curved \:surface\: area\: \\ + \:Outer \:curved \: surface\: area$



= ( 15.4 + 15.75 ) sq.m



= 31.15 sq.m



Now,



Cost of painting per sq.m = Rs. 2



$\therefore Cost \:of \:painting \:31.15\: sq.m\: \\ =\: Rs. ( 2 × 31.15 )$



${\boxed{ \therefore \: your \: answer \:= Rs. 62.30}}$



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Answer 2

Answer is in attachment

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