Question

Derive laws of resistance in series so as to explain
equivalent resistance of circuito​

Answer 1

Answer:

The equivalent resistance is the algebraic sum of the resistances (Equation 10.3. 2): RS=R1+R2+R3+R4+R5=20Ω+20Ω+20Ω+20Ω+10Ω=90Ω. The current through the circuit is the same for each resistor in a series circuit and is equal to the applied voltage divided by the equivalent resistance: I=VRS=9V90Ω=0.1A.

Answer 2

Answer:

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