Derive of v2_u2= 2as.equation
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Explanation:
We will use both of the equations of motion to reach the third equation of motion. This will require a bit of algebra.
S=ut+21at2andv=u+at, include the time variant t
There will be some situations when we do not have any information about time and so it would be a good idea to derive an equation that does not have a t term.
To do this, we rearrange our first equation to get
t=av−u
and use this to replace t wherever it appears in the second equation. So
S=ut+21at2 becomes,
S=u(av−u)+21a(av−u)2
⇒2aS=2u(v−u)+(v−u)2
⇒2aS=2uv−2u2−v2−2uv−u2
⇒2aS=v2−u2
⇒v2=u2+2aS
*Hope it helped you*
Answered by
1
Explanation:
v²–u²=2as
we know in second equation
s = ut + 1/2 a t²
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