derive- p=mgh & k=half mv^2
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★P = mgh
We consider a ball of mass 'm' . It is taken to a height 'h' from the ground. To take the ball to the top some force would have acted.
Let , F = mg
Ball gains energy = W X D on it.
Work done on ball to take it to this height = F x D
=mg x h.
Whatever work done on the ball is stored as P.E.
∴ P.E = mgh.
We consider a ball of mass 'm' . It is taken to a height 'h' from the ground. To take the ball to the top some force would have acted.
Let , F = mg
Ball gains energy = W X D on it.
Work done on ball to take it to this height = F x D
=mg x h.
Whatever work done on the ball is stored as P.E.
∴ P.E = mgh.
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