Derive position time relation by algebraic method
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hey mate!!
Explanation:
the distance traveled by the object is obtained by the area enclosed within OABC under the velocity-time graph.
s=areavof rectangleOABC+area of triangle ABO
=OA X OC +1/2(AD X BD)
since,
OC=AD=t
OA=u
BD=at
s=u X t + 1/2(t X at)
s=ut+1/2at(squ.)
(s=ut+1/2at square) (pronounsation)
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