derive relation between R=R1+R2+R3 when three resistor R1,R2 and R3 are connected in the series in an electric circuit
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Consider 3 Resistors with resistance R₁, R₂ & R₃. All there are connected to a cell with voltage of V. Potential Difference across R₁, R₂ & R₃ are V₁, V₂ & V₃ respectively. All these 3 Potential difference make a total of V
V = V₁ + V₂ + V₃
Now the current flowing through the circuit be I.
By Ohm's Law, we know that :
V = I × R
Current will be same through whole circuit. Now let us separate the relation between the each resistors, current flowing and Voltage.
V₁ = I × R₁
V₂ = I × R₂
V₃ = I × R₃
Now using (1) here
V = IR₁ + IR₂ + IR₃
IR = = IR₁ + IR₂ + IR₃
Dividing both sides by I
R = R₁ + R₂ + R₃
The sum of all resistors in a circuit in a series is equal to Total resistance in the series.
ahanao88:
Thanks
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