Question

Derive second equation of motion, s = ut + 1/2 at2 graphically where the symbols have their usual meanings.

Answer 1

$\huge \bf{hey}$

$\huge{ \mathfrak{here \: is \: answer}}$

$\bf{see \: in \: pic}$

hey dear

s= area of trapezium OABD..

since ,trapezium is made up of triangle and rectangle

hence,

s= area of triangleABC + area of rectangle OACD

hence

1/2 base* height + length * breadth

hence i have solve it


see in pic


$\huge{ \ulcorner{hope \: it \: helps}}$

$\huge{ \mathbb{THANKS}}$

Answer 2

$\underline \bold {\boxed {Derivation \: Of \: Second \: Law}}$

As area under velocity time graph = distance travelled = s

Area of Triangle + Area of rectangle

ADB + AOCD

S = 1/2 × EB × CB + OA × OE - - - (1)

As the EB - - - OA = t
CB = DE

AS,

OD = V, OE = U

CB = DE = OD - OE

➡️ V - U

Putting above values in (1)

S = 1/2 (t) (v-u) + t(v)

➡️ ut + 1/2 ( v-u) t

By Ist equation of motion, v - u = at

S = ut + 1/2 at^2

$\huge \bold {\boxed {HENCE, PROVED}}$