Question

Derive the 2nd and 3rd equation of motion mathematically

Answer 1

hope it will help you..........................

Answer 2

Answer:

Explanation:

second equation

displacement=avg velocity.time

s =(u+v/2).t

from v=u+at

we can derive t=v-u/a

now put this equation

s=(u+v/2)(v-u/a)

s=v^2-u^2/2a

  2as=v^2-U^2

third equation

s=(v+u/2)t

   put v=u+at

s=(u+at+u/2)t

s=(2u/2+at/2)t

s=(u+1/2at)t

  s=ut+1/2at^2

 hence proved

                                        hope it helps you