derive the edge length radius relation of bcc structure
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This question is of solid state. in BCC structure, one atom is placed in centre of cubic lattice . due to this reason , co-ordination number of bcc is 8. and number of atom per unit cell = 2.
see figure, here we can see a cubic lattice is shown. this cubic lattice is not other than bcc.
Let edge length of bcc is a
and r is the radius of each atom,
then, you can see,
then diagonal of bcc = r + 2r + r
√3a = 4r
a = 4r/√3
hence, relation between edge length and radish is a = 4r/√3
see figure, here we can see a cubic lattice is shown. this cubic lattice is not other than bcc.
Let edge length of bcc is a
and r is the radius of each atom,
then, you can see,
then diagonal of bcc = r + 2r + r
√3a = 4r
a = 4r/√3
hence, relation between edge length and radish is a = 4r/√3
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