Question

derive the equation for position-time relation​

Answer 1

HEY MATE...

HERE IS YOUR ANSWER...

POSITION TIME RELATION MEANS .....
v=u+1/2at^2

LET AN OBJECT STARTS FROM A POINT WITH INITIAL VELOCITY u AFTER t SECOND IT ATTAINS A FINAL VELOCITY v WITH ACCELERATION a AND DURING THIS JOURNEY THE DISTANCE COVERED IS S.

Distance = average velocity × TIME
S = u +v / 2 × t
S = u + u+at / 2 × t ( v = u + at ..from first equation of motin)
S = 2u + at / 2 ×t
S=2ut + at^2 /2
S=2ut + at^2/2
S= 2ut/2 + at^2/2
S= ut + 1/2 at^2.... proved ( 2ut/2 2 ...2 cancel )

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PLS MARK AS BRAINLIEST.