Derive the equation for position velocity relation by graphical method
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Equation for position velocity relation
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Answer: we know that distance travelled s by a body in time t is given by the area under line AB which is area of trapezium OABC.
So we have
Distance travelled =s=Area of trapezium OABC
S=Sum of parallel side × height /2
=(OA+CB) ×OC /2
Since OA+CB =U+V and OC = t,
Than we get
S= (u+v) t/2get-eq1
From velocity time relation
t=u-v/a
Substitute the value of 't' in equation 1
We get,
s=(u+v) /2(u-v) /2
Or we have
v^2=u^2+2as
which is equation for position velocity relation
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