Question

Derive the equation for velocity of projectile

Answer 1

x = u cosθ × t

 

t = x/(u cosθ)                                                   ...... (1)

 

The vertical distance travelled by projectile is given from kinematical equation s = ut + ½at2.

Here, s = y, a = ay = -g, u = uy = u sinθ

 

Thus, we have

 

y = u sinθ - ½gt2                                              ...... (2)

 

Substituting equation (1) in (2), we get

y=xtanθ−gx^2/2v^2cos^2(θ)

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Answer 2

Projectile Motion equation derivation – parabola

The velocity component along X axis = V0x = V0 cosθ and the velocity component along Y axis = V0y = V0sinθ.✔️✔️