Question

derive the equation of motion s=ut+1/2at^2 by graphically​

Answer 1

HEY MATE!!!!!..

At t = 0, initial velocity = u = OA  

At t = t, final velocity = v = OC

The distance S travelled in time t = area of the trapezium OABD

s = (1/2) x (OA + DB) × OD

s = (1/2) x (u + v) × t  

Since v = u + at,

s = (1/2) x (u + u + at) × t

s = ut + (1/2) at2..

PLZ MARK IT BRAINLIEST ANSWER!!