Derive the equation of motion V2-U2=2as numerically
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s=ut+1/2 at²
v=u+at
at=v-u
t=(v-u)/a
Putting the value of t in second equation
s= u(v-u)/a+1/2 a((v-u)/a)²
s=(uv-u²)/a+(a(v²+u²-2vu))2a² (v-u)²=v²+u²-2vu
s=(uv-u²)/a + (v²+u²-2vu)2a
s=(2uv-2u²+v²+u²-2uv)/2a
2as=v²-u²
Hope this helps you.
Plz mark me brainliest if it helps you.
v=u+at
at=v-u
t=(v-u)/a
Putting the value of t in second equation
s= u(v-u)/a+1/2 a((v-u)/a)²
s=(uv-u²)/a+(a(v²+u²-2vu))2a² (v-u)²=v²+u²-2vu
s=(uv-u²)/a + (v²+u²-2vu)2a
s=(2uv-2u²+v²+u²-2uv)/2a
2as=v²-u²
Hope this helps you.
Plz mark me brainliest if it helps you.
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