derive the equation of the plane perpendicular to a given vector and passing through a given point both in vector and cartesian form
Answers
Answer:
Let us suppose that our varying plane vector from a fixed point is r
and, the given point through which the plane passes be a
Now, let the given vector which is perpendicular to the plane be n
Clearly, from geometrical intuition,
r-a vector will be perpendicular to the vector n
Which implies that their scalar or dot product must be zero.
So,
(r-a). n = 0
or,
r.n = a.n
This is the vector equation.
Now for the equation in Cartesian form
Suppose
r = x i^ + y j^ + z k^
and, point vector
n = n1 i^ + n2 j^ + n3 k^
Which finally leads from the vector equation that
n1 x + n2 y + n3 z = d
where, d is a scalar = a.n
Hope this helps you !!
Answer:
Let us suppose that our varying plane vector from a fixed point is r
and, the given point through which the plane passes be a
Now, let the given vector which is perpendicular to the plane be n
Clearly, from geometrical intuition,
r-a vector will be perpendicular to the vector n
Which implies that their scalar or dot product must be zero.
So,
(r-a). n = 0
or,
r.n = a.n
This is the vector equation.
Now for the equation in Cartesian form
Suppose
r = x i^ + y j^ + z k^
and, point vector
n = n1 i^ + n2 j^ + n3 k^
Which finally leads from the vector equation that
n1 x + n2 y + n3 z = d
where, d is a scalar = a.n