Derive the equation: v=u+at
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Answered by
176
t=time
a= acceleration
v=velocity
u=initial velocity
a=(v-u)/t
at=v-u
at+u=v
Therefore v=u+at
a= acceleration
v=velocity
u=initial velocity
a=(v-u)/t
at=v-u
at+u=v
Therefore v=u+at
Answered by
136
Consider the graph attached below:
The linear motion of a body with initial velocity - u
The body accelerates uniformly with - a
Time - t
And aquires final velocity - v
The velocity-time graph is a straight line DB.
Initial velocity = OD = u
Final Velocity = OC = v
Acceleration = Slope of line DB,
Acceleration (a)
a = AB / AD
a = DC / OE
a = (OC-OD) / OE
a = (v-u) / t
at = v-u
v = u + at
The linear motion of a body with initial velocity - u
The body accelerates uniformly with - a
Time - t
And aquires final velocity - v
The velocity-time graph is a straight line DB.
Initial velocity = OD = u
Final Velocity = OC = v
Acceleration = Slope of line DB,
Acceleration (a)
a = AB / AD
a = DC / OE
a = (OC-OD) / OE
a = (v-u) / t
at = v-u
v = u + at
Attachments:
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