Question

Derive the expression for 2nd Equation of motion (Position-Time
relation)?​

Answer 1

Step-by-step explanation:

Distance S = Area of trapezium ABDO

= Area of rectangle ACDO+ Area of traingle ABC

= OD×OA+1/2BC×AC

= t×u+1/2(v-u) t

= ut+1/2 (at) t (v=u+at)

= ut+1/2at^2