Derive the expression for 2nd Equation of motion (Position-Time
relation)?
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Step-by-step explanation:
Distance S = Area of trapezium ABDO
= Area of rectangle ACDO+ Area of traingle ABC
= OD×OA+1/2BC×AC
= t×u+1/2(v-u) t
= ut+1/2 (at) t (v=u+at)
= ut+1/2at^2
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