Example 3: A kangaroo can jump 2.5 m
vertically. What must be the initial velocity
of the kangaroo?
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Answer: 7m/s
Explanation:First remember the equation : vsquare - u square =2as
So, 2as=v square - u square
2as+v square = - u square
Substituting them :
2*9.8*2.5 + 0square = - usquare
49 +0 = - usquare
u square = - 49
u = root of 49
u = 7m/s
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