History, asked by Anonymous, 1 year ago

Derive the expression for Joule's heating effect of current..

Give applications also plz

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Answered by DIVINEREALM
27

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JOULE'S HEATING EFFECT

ᴀᴄᴄᴏʀᴅɪɴɢ ᴛᴏ ᴊᴏᴜʟᴇꜱ ʟᴀᴡ ᴏꜰ ʜᴇᴀᴛɪɴɢ, ᴡʜᴇɴ ᴀ ᴄᴜʀʀᴇɴᴛ ɪ ꜰʟᴏᴡꜱ ᴛʜʀᴏᴜɢʜ ᴀ ʀᴇꜱɪꜱᴛᴀɴᴄᴇ ʀ ᴛʜᴇɴ :

ʜᴇᴀᴛ ᴘʀᴏᴅᴜᴄᴇᴅ ɪꜱ :

(ɪ) ᴅɪʀᴇᴄᴛʟʏ ᴘʀᴏᴘᴏʀᴛɪᴏɴᴀʟ ᴛᴏ ᴛʜᴇ ꜱQᴜᴀʀᴇ ᴏꜰ ᴄᴜʀʀᴇɴᴛ ꜰᴏʀ ᴀ ɢɪᴠᴇɴ ʀᴇꜱɪꜱᴛᴀɴᴄᴇ

(ɪɪ) ᴅɪʀᴇᴄᴛʟʏ ᴘʀᴏᴘᴏʀᴛɪᴏɴᴀʟ ᴛᴏ ᴛʜᴇ ʀᴇꜱɪꜱᴛᴀɴᴄᴇ ᴏꜰ ɢɪᴠᴇɴ ᴄɪʀᴄᴜɪᴛ.

(ɪɪɪ) ᴅɪʀᴇᴄᴛʟʏ ᴘʀᴏᴘᴏʀᴛɪᴏɴᴀʟ ᴛᴏ ᴛʜᴇ ᴛɪᴍᴇ ꜰᴏʀ ᴡʜɪᴄʜ ᴛʜᴇ ʀᴇꜱɪꜱᴛᴀɴᴄᴇ ꜰʟᴏᴡꜱ ᴛʜʀᴏᴜɢʜ ᴛʜᴇ ʀᴇꜱɪꜱᴛᴏʀ.

So eqⁿ is \bold{\huge{\red{H=I^2Rt}}}

\bold{\huge{\boxed{\pink{DERIVATION}}}}

ʟᴇᴛ ᴜꜱ ᴄᴏɴꜱɪᴅᴇʀ ᴀ ʀᴇꜱɪꜱᴛᴀɴᴄᴇ ʀ , ɪɴ ᴡʜɪᴄʜ ɪ ᴀᴍᴏᴜɴᴛ ᴏꜰ ᴄᴜʀʀᴇɴᴛ ꜰʟᴏᴡꜱ.

ᴡᴏʀᴋ ᴍᴜꜱᴛ ʙᴇ ᴅᴏɴᴇ ʙʏ ᴄᴜʀʀᴇɴᴛ ᴛᴏ ᴍᴏᴠᴇ ᴄᴏɴᴛɪɴᴜᴏᴜꜱʟʏ.

ᴡ=Qx ᴠ

ʙᴜᴛ Q=ɪxᴛ

ᴡ=ɪxᴠxᴛ

ʙᴜᴛ ꜰʀᴏᴍ ᴏʜᴍꜱ ʟᴀᴡ: ᴠ=ɪʀ

\bold{\huge{\red{W=I^2Rt}}}

ᴀꜱꜱᴜᴍɪɴɢ ᴛʜᴇ ᴇʟᴇᴄᴛʀɪᴄᴀʟ ᴇɴᴇʀɢʏ ᴄᴏɴꜱᴜᴍᴇᴅ ɪꜱ ᴄᴏɴᴠᴇʀᴛᴇᴅ ɪɴᴛᴏ ʜᴇᴀᴛ ᴇɴᴇʀɢʏ .

ᴡᴇ ᴡʀɪᴛᴇ ᴡᴏʀᴋ ᴅᴏɴᴇ ᴀꜱ ʜᴇᴀᴛ  ᴘʀᴏᴅᴜᴄᴇᴅ.

so \bold{\underline{\huge{\red{H=I^2Rt}}}}

\bold{\huge{\boxed{\pink{APPLICATION}}}}

❶ ɪɴ ᴇʟᴇᴄᴛʀɪᴄᴀʟ ʜᴇᴀᴛᴇʀꜱ.

❷ ɪɴ ᴇʟᴇᴄᴛʀɪᴄᴀʟ ɪʀᴏɴ

❸ ɪɴ ᴇʟᴇᴄᴛʀɪᴄᴀʟ ꜰᴜꜱᴇ ᴡɪʀᴇ

❹ ɪɴ ᴇʟᴇᴄᴛʀɪᴄᴀʟ ʙᴜʟʙ

<marquee direction="left" height="80" behavior="scroll" >LovePhysicsandGenerateHeat</marquee>

\bold{\huge{\boxed{\red{\mathscr{ThankYou}}}}}

\bold{\underline{\huge{\red{\mathscr{PlzMarkBrainliest}}}}}

Answered by AcsahJosemon
1

Answer:

Hence the heating effect produced by an electric current, I through a conductor of resistance, R for a time, t is given by H = I2Rt. ... Joule's law states the amount of heat production in a conductor is : Directly proportional to the square of electric current flowing through it.

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