write a linear polynomial whose zeeoes are 4 and 5
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Answered by
0
Answer:
Step-by-step explanation:
If you want 4 and 5 to be zeroes,then the factors must be;
(x-4) and (x-5)
Polynomial: (x-4)(x-5)
=x^2-5x-4x+20
=x^2-9x+20
Answered by
0
Answer:x^2-9x+20=0 is required polynomial
Step-by-step explanation : since relationship are
X+Z=-(b)/a (where X and Z are zeros )
4+5=-(b)/a
9=-(b)/a
And
X×Z=c/a
4×5=c/a
20=c/a
Here
a=1
b=-9
and c=2 therefore
x^2-9x+20=0 is required polynomial
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