Derive the expression for K.E of body having mass m moving with the speed of V meter per sec
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PROOF~
HERE YOU GO
Consider a body of mass "m" starts moving from rest. After a time interval "t" its velocity becomes V.
If initial velocity of the body is Vi = 0 ,final velocity Vf = V and the displacement of body is "d". Then
First of all we will find the acceleration of body.
Using equation of motion
2aS = Vf^2 – Vi^2
Putting the above mentioned values
2ad = V^2 – 0
a = V^2/2d
Now force is given by
F = ma
Putting the value of acceleration
F = m(V^2/2d)
As we know that
Work done = Fd
Putting the value of F
Work done = (mv2/2d)(d)
Work done = mV^2/2
OR
Work done = ½ mV^2
Since the work done is motion is called "Kinetic Energy"
i.e.
K.E. = Work done
OR
K.E. =1/2mV^2
HOPE IT HELPS YOU .........
THANKS........
@anmol
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