Derive the Expression for Molecular velocities.
Answers
Answer: Root mean square velocity vmn=(V2−)=3KBTm−−−−−−√, where 'm' is the mass of the molecule, k - Boltzmann constant and T is the absolute scale of temperature.
Answer:
Expression for the average molecular velocity of gas molecules are (where R is the gas constant, T is temperature and, M is the mass of the molecule)
Explanation:
- Formula used:
- In this case, the probability density function P(v) is the Maxwell-Boltzmann distribution and the quantity we want to find the expectation value is simply the velocity v.
- . We know velocity can only be positive. So we have the limit from zero to ∞
- Therefore, the mean velocity is given by,
- Where, P(v)is the Maxwell-Boltzmann distribution given as,
- Where m is the mass of the gas molecule. k is the Boltzmann constant, T is the given temperature, and v is the velocity of one molecule.
- So, the average velocity is given as,
- The result of integral in this form is given as,
- So, here we have
⇒
⇒
- Here, m is the mass of one molecule. If we take the mass of the compound as M, they are related by M=Nm (Where N is the Avogadro's number)
- Since, R=Nk, where R is the gas constant, we can modify the equation as,
- So, we have found the average velocity of a gas molecule as
Learn more about Maxwell-Boltzmann distribution:
https://brainly.in/question/1822855
Learn more about Avogadro's number:
https://brainly.in/question/762547
#SPJ3