Physics, asked by abhisheksingh258, 7 hours ago

derive the expression for the electric potential at any point along the axial line of an electric dipole and it's S.I. unit and dimension?​

Answers

Answered by NITESH761
0

Answer:

Let P be an axial point at distance r from the centre of the dipole. Electric potential at Point P will be

`V=V_(1)+V_(2)=-(1)/(4 pi in_(0))(q)/(r+a)+(1)/(4 pi in_(0)).(q)/(r-a)=(q)/(4pi in_(0))[(1)/(r-a)-(1)/(r+a)]=(q)/(4pi in_(0)).(2a)/(r^(2)-a^(2))`

`=(1)/(4pi in_(0)).(p)/(r^(2)-a^(2)) " " [:' p=q(2a)]`

For a far away point, `r gt gt a " " :. V=(1)/(4 pi in_(0)).(p)/(r^(2))`.

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