derive the expression for the equivalent resistance in series and combination of resistor
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Two resistors of resistance R1 and R2 are connected in series. Let I be the current through the circuit. The current through each resistor is also I. The two resistors joined in series is replaced by an equivalent single resistor of resistance R such that the potential difference V across it, and the current I through the circuit remains same.
As , V = IR , V1 = IR1 , V2 = IR2
IR = IR1 + IR2
IR = I (R1 + R2)
there fore R=(R1+ R2)
As , V = IR , V1 = IR1 , V2 = IR2
IR = IR1 + IR2
IR = I (R1 + R2)
there fore R=(R1+ R2)
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Explanation:
Irfanshaik1Ambitious
Two resistors of resistance R1 and R2 are connected in series. Let I be the current through the circuit. The current through each resistor is also I. The two resistors joined in series is replaced by an equivalent single resistor of resistance R such that the potential difference V across it, and the current I through the circuit remains same.
As , V = IR , V1 = IR1 , V2 = IR2
IR = IR1 + IR2
IR = I (R1 + R2)
there fore R=(R1+ R2)
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