Question

derive the expression for the equivalent resistance in series and combination of resistor

Answer 1

Two resistors of resistance R1 and R2 are connected in series. Let I be the current through the circuit. The current through each resistor is also I. The two resistors joined in series is replaced by an equivalent single resistor of resistance R such that the potential difference V across it, and the current I through the circuit remains same. 

As , V = IR , V1 = IR1 , V2 = IR2 

                                  IR = IR1 + IR2 

                                  IR = I (R1 + R2)

there fore R=(R1+ R2)

Answer 2

Answer:

Explanation:

Irfanshaik1Ambitious

Two resistors of resistance R1 and R2 are connected in series. Let I be the current through the circuit. The current through each resistor is also I. The two resistors joined in series is replaced by an equivalent single resistor of resistance R such that the potential difference V across it, and the current I through the circuit remains same. 

As , V = IR , V1 = IR1 , V2 = IR2 

                                  IR = IR1 + IR2 

                                  IR = I (R1 + R2)

there fore R=(R1+ R2)