Question

derive the expression for the torque acting on a current carrying loop placed in a magnetic field​

Answer 1

Answer:

A rectangular loop ABCD of dimensions l and b, carrying a steady current is placed in uniform magnetic field as shown in fig; such that normal of the plane is at angle θ with the magnetic field lines. The force FBC and FAD on arms BC and AD are equal, opposite and along the axis of the coil, so they cancel each other. The forces FAB and FCD are also equal and opposite, but are not collinear, so they constitute a couple, and the magnitude of the torque can be given