Question

Derive the expression of for the moment of inertia of a thin uniform circular ring about an axis through its centre

Answer 1

Answer:

The movement of inertia of ring about and axis passing through center perpendicular to the phase

Explanation:

if is movement of inertia of a thin rod about an axis perpendicular to the length and passing its center and its movement inertia when is is bent into a shape of ring then its perpendicular to its phase

Answer 2

$\textbf{Answer is in attachment!}$