Question

derive the expression of interpetal acceleration force​

Answer 1

Answer:

Hence, vector form of centripetal acceleration is: →a=−ωR2(sinωt ˆi+cosωt ˆj) which shows that it's direction is towards the centre and along the string at every point of circular track. Hence centripetal acceleration is ωR2.

Answer 2

$\huge \tt \green{answer : }$

Centripetal force : Rateof change of tangential velocity is called as the centripetal acceleration.

the derivation is given in the attachment...