Question

derive the expression of maximum speed of circular motion of a car on level road​

Answer 1

Explanation:

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Answer 2

Answer:

v=$\sqrt( tan\alpha +u/1-u tan\alpha)rg$

Explanation:

Let the radius of circular road be R,

leveled at an angle α,

and a car of mass m rotates around the circular road.

So ,we have Fnet (towards the centre of road)=mv²/R

For the car,

In the X-axis equation of forces is:

R sinα + N cosα= mv²/R      ⇒1

In the Y-axis equation of forces is:

R cosα - N sinα = mg     ⇒2

Now, divide the equation 1 by equation 2

We get,

(R sinα + N cosα)/R cosα - N sinα= (mv²/R)/mg    ⇒3

we have N/R=u

and dividing the  equation 3 by R cosα

we get,

(tanα +u)/(1-u tanα)=v²/Rg

From this we obtain the expression of v (velocity of car on road)

v=$\sqrt (tan\alpha + u/1- utan\alpha)Rg$